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3599. The const overload of lazy_split_view::begin should be constrained by const Pattern

Section: [range.lazy.split.view] Status: New Submitter: Hewill Kang Opened: 2021-09-23 Last modified: 2021-10-17

Priority: 3

View all other issues in [range.lazy.split.view].

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Consider the following code snippet:

#include <ranges>

int main() {
  auto p = std::views::iota(0)
         | std::views::take(1)
         | std::views::reverse;
  auto r = std::views::single(42)
         | std::views::lazy_split(p);
  auto f = r.front();

r.front() is ill-formed even if r is a forward_range.

This is because the const overload of lazy_split_view::begin is not constrained by the const Pattern, which makes it still well-formed in such cases. When the const overload of view_interface<lazy_split_view<V, Pattern>>::front is instantiated, the subrange{parent_->pattern_} inside lazy_split_view::outer-iterator<true>::operator++() will cause a hard error since const Pattern is not a range.

[2021-09-24; Daniel comments]

This issue is related to LWG 3592.

[2021-10-14; Reflector poll]

Set priority to 3 after reflector poll.

Proposed resolution:

This wording is relative to N4892.

  1. Modify [range.lazy.split.view], class template lazy_split_view synopsis, as indicated:

    namespace std::ranges {
      template<input_range V, forward_range Pattern>
        requires view<V> && view<Pattern> &&
                 indirectly_comparable<iterator_t<V>, iterator_t<Pattern>, ranges::equal_to> &&
                (forward_range<V> || tiny-range<Pattern>)
      class lazy_split_view : public view_interface<lazy_split_view<V, Pattern>> {
        constexpr auto begin() {
        constexpr auto begin() const requires forward_range<V> && forward_range<const V> &&
                                              forward_range<const Pattern>{
          return outer-iterator<true>{*this, ranges::begin(base_)};
        constexpr auto end() requires forward_range<V> && common_range<V> {
        constexpr auto end() const {
          if constexpr (forward_range<V> && forward_range<const V> && common_range<const V> &&
                        forward_range<const Pattern>)
            return outer-iterator<true>{*this, ranges::end(base_)};
            return default_sentinel;