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move_iterator operator+()
has incorrect constraintsSection: 24.5.4.9 [move.iter.nonmember] Status: C++23 Submitter: Bo Persson Opened: 2019-09-13 Last modified: 2023-11-22
Priority: 3
View all other issues in [move.iter.nonmember].
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Discussion:
Section 24.5.4.9 [move.iter.nonmember]/2-3 says:
template<class Iterator> constexpr move_iterator<Iterator> operator+(iter_difference_t<Iterator> n, const move_iterator<Iterator>& x);Constraints:
Returns:x + n
is well-formed and has typeIterator
.x + n
.
However, the return type of this operator is move_iterator<Iterator>
, so
the expression x + n
ought to have that type. Also, there is no operator+
that matches the constraints, so it effectively disables the addition.
[2019-10-31 Issue Prioritization]
Priority to 3 after reflector discussion.
Previous resolution [SUPERSEDED]:This wording is relative to N4830.
Modify 24.5.4.9 [move.iter.nonmember] as indicated:
template<class Iterator> constexpr move_iterator<Iterator> operator+(iter_difference_t<Iterator> n, const move_iterator<Iterator>& x);-2- Constraints:
-3- Returns:x + n
is well-formed and has typemove_iterator<Iterator>
.x + n
.
[2019-11-04; Casey comments and provides revised wording]
After applying the P/R the Constraint element requires x + n
to be well-formed (it always is,
since that operation is unconstrained) and requires x + n
to have type
move_iterator<Iterator>
(which it always does). Consequently, this Constraint
is always satisfied and it has no normative effect. The intent of the change in
P0896R4 was that this operator be constrained to require
addition on the base iterator to be well-formed and have type Iterator
, which ensures that
the other semantics of this operation are implementable.
[2021-06-23; Reflector poll]
Set status to Tentatively Ready after six votes in favour during reflector poll.
[2021-10-14 Approved at October 2021 virtual plenary. Status changed: Voting → WP.]
Proposed resolution:
This wording is relative to N4835.
Modify 24.5.4.9 [move.iter.nonmember] as indicated:
template<class Iterator> constexpr move_iterator<Iterator> operator+(iter_difference_t<Iterator> n, const move_iterator<Iterator>& x);-2- Constraints:
-3- Returns:x.base() + n
is well-formed and has typeIterator
.x + n
.