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scoped_allocator_adaptor::construct()
Section: 20.2.8.2 [allocator.uses.construction] Status: C++20 Submitter: Jonathan Wakely Opened: 2019-02-14 Last modified: 2021-02-25
Priority: Not Prioritized
View all other issues in [allocator.uses.construction].
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Discussion:
2586(i) fixed the value category in the uses-allocator checks done by scoped_allocator_adaptor
.
When we made that use uses_allocator_construction_args
we reintroduced the problem, because that
function has the same bug.
#include <memory> struct X { using allocator_type = std::allocator<X>; X(std::allocator_arg_t, allocator_type&&) { } X(const allocator_type&) { } }; int main() { std::allocator<X> a; std::make_obj_using_allocator<X>(a); }
This will fail to compile, because uses_allocator_construction_args
will check is_constructible
using an rvalue allocator, but then return tuple<allocator_arg_t, const allocator<X>&>
containing an lvalue allocator. Those args cannot be used to construct an X
.
[2019-02; Kona Wednesday night issue processing]
Status to Ready
Proposed resolution:
This wording is relative to N4800.
Change 20.2.8.2 [allocator.uses.construction] as indicated:
[Drafting Note: Arguably the
uses_allocator
specialization should also useconst Alloc&
but in practice that doesn't matter, except for even more contrived cases than the very contrived example above.]
template <class T, class Alloc, class... Args> auto uses_allocator_construction_args(const Alloc& alloc, Args&&... args) -> see below;[…]
-5- Returns: Atuple
value determined as follows:[…]
(5.1) — If
uses_allocator_v<T, Alloc>
isfalse
andis_constructible_v<T, Args...>
istrue
, returnforward_as_tuple(std::forward<Args>(args)...)
.(5.2) — Otherwise, if
uses_allocator_v<T, Alloc>
istrue
andis_constructible_v<T, allocator_arg_t, const Alloc&, Args...>
istrue
, returntuple<allocator_arg_t, const Alloc&, Args&&...>( allocator_arg, alloc, std::forward<Args>(args)...)(5.3) — Otherwise, if
uses_allocator_v<T, Alloc>
istrue
andis_constructible_v<T, Args..., const Alloc&>
istrue
, returnforward_as_tuple(std::forward<Args>(args)..., alloc)
.(5.4) — Otherwise, the program is ill-formed.