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time_of_day
and durations that seconds
cannot convert toSection: 30.9 [time.hms] Status: Resolved Submitter: Richard Smith Opened: 2018-03-24 Last modified: 2021-06-06
Priority: 2
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Discussion:
What should happen here:
const int bpm = 100; using beats = duration<int, ratio<60, 100>>; auto v = time_of_day<beats>(beats{2}).subseconds();
? 2 beats at 100bpm is 1.2
seconds. The time_of_day
constructor specification says:
seconds()
returns the integral number of secondssince_midnight
is after(00:00:00 + hours() + minutes())
.subseconds()
returns the integral number of fractional precision secondssince_midnight
is after(00:00:00 + hours() + minutes() + seconds())
.
But that's impossible. If seconds()
returns 1, we need to return a subseconds()
value representing 0.2s
of type precision
, but type precision
can only represent multiples of 0.6s
.
time_of_day
specialization only be available for the case where seconds
is convertible to
precision
? Or should the precision
type used by this specialization be
common_type_t<seconds, duration<Rep, Period>>
rather than merely duration<Rep, Period>
?
Either way I think we need a wording update to specify one of those two behaviors.
[2018-04-09 Priority set to 2 after discussion on the reflector.]
[2019 Cologne Wednesday night]
Status to Resolved (group voted on NAD, but Marshall changed it to Resolved)
Resolved by the adoption of P1466 in Cologne.
hh_mm_ss
is now specified such that subseconds must be a
non-positive power of 10 (e.g. 1/10s, 1/100s, milliseconds, etc.). In
this example 60/100 simplifies to 3/5, which can be exactly represented
with 1 fractional decimal digit. So in this example subseconds()
has
the value of 2ds
(2 deciseconds).
Proposed resolution: