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pmr::string
and friendsSection: 27.4.6 [basic.string.hash], 27.4.2 [string.syn] Status: C++20 Submitter: Tim Song Opened: 2017-06-14 Last modified: 2021-02-25
Priority: 0
View all other issues in [basic.string.hash].
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Discussion:
In most cases, std::pmr::meow
is a drop-in replacement for std::meow
. The exception is
std::pmr::{,w,u16,u32}string
, because unlike their std::
counterparts, they don't come with enabled
std::hash
specializations.
The P/R below simply adds std::hash
specializations for those four typedefs. An alternative approach, for which wording can be
produced if desired, is to make the hash
specializations for basic_string
allocator-agnostic, similar to the partial
specialization of hash
for vector<bool>
.
[2017-07 Toronto Monday issue prioritization]
Priority 0; move to Ready
Proposed resolution:
This wording is relative to N4659.
Edit 27.4.2 [string.syn], header <string>
synopsis, as indicated:
namespace pmr { template <class charT, class traits = char_traits<charT>> using basic_string = std::basic_string<charT, traits, polymorphic_allocator<charT>>; using string = basic_string<char>; using u16string = basic_string<char16_t>; using u32string = basic_string<char32_t>; using wstring = basic_string<wchar_t>; } // 27.4.6 [basic.string.hash], hash support template<class T> struct hash; template<> struct hash<string>; template<> struct hash<u16string>; template<> struct hash<u32string>; template<> struct hash<wstring>; template<> struct hash<pmr::string>; template<> struct hash<pmr::u16string>; template<> struct hash<pmr::u32string>; template<> struct hash<pmr::wstring>;namespace pmr { template <class charT, class traits = char_traits<charT>> using basic_string = std::basic_string<charT, traits, polymorphic_allocator<charT>>; using string = basic_string<char>; using u16string = basic_string<char16_t>; using u32string = basic_string<char32_t>; using wstring = basic_string<wchar_t>; }
Edit 27.4.6 [basic.string.hash] as indicated:
template<> struct hash<string>; template<> struct hash<u16string>; template<> struct hash<u32string>; template<> struct hash<wstring>; template<> struct hash<pmr::string>; template<> struct hash<pmr::u16string>; template<> struct hash<pmr::u32string>; template<> struct hash<pmr::wstring>;-1- If
S
is one of these string types,SV
is the corresponding string view type, ands
is an object of typeS
, thenhash<S>()(s) == hash<SV>()(SV(s))
.