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std::throw_with_nested("string_literal")
Section: 17.9.8 [except.nested] Status: C++17 Submitter: Jonathan Wakely Opened: 2017-01-17 Last modified: 2020-09-06
Priority: 0
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Discussion:
[except.nested] says:
template <class T> [[noreturn]] void throw_with_nested(T&& t);Let
Requires:U
beremove_reference_t<T>
.U
shall beCopyConstructible
.
This forbids std::throw_with_nested("string literal")
because T
gets deduced as const char(&)[15]
and so U
is const char[15]
which is not CopyConstructible
.
throw_with_nested
also worked fine until I added a static_assert
to enforce the
CopyConstructible
requirement.
The same problem exists when throwing a function type, which should also decay:
#include <exception> void f() { } int main() { std::throw_with_nested(f); }
(Note: LWG 1370(i) added the remove_reference
, which was a step in the right direction but not far enough.)
[2017-01-27 Telecon]
Priority 0
Proposed resolution:
This wording is relative to N4618.
Edit 17.9.8 [except.nested] as indicated:
template <class T> [[noreturn]] void throw_with_nested(T&& t);-6- Let
-7- Requires:U
be.
remove_referencedecay_t<T>U
shall beCopyConstructible
.