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allocator_traits::max_size()
default behavior is incorrectSection: 16.4.4.6 [allocator.requirements], 20.2.9.3 [allocator.traits.members] Status: C++17 Submitter: Howard Hinnant Opened: 2015-01-17 Last modified: 2017-07-30
Priority: 3
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Discussion:
Table 28 — "Allocator requirements" says that default behavior for a.max_size()
is
numeric_limits<size_type>::max()
. And this is consistent with the matching statement
for allocator_traits
in 20.2.9.3 [allocator.traits.members]/p7:
static size_type max_size(const Alloc& a) noexcept;Returns:
a.max_size()
if that expression is well-formed; otherwise,numeric_limits<size_type>::max()
.
However, when allocating memory, an allocator must allocate n*sizeof(value_type)
bytes, for example:
value_type* allocate(std::size_t n) { return static_cast<value_type*>(::operator new (n * sizeof(value_type))); }
When n == numeric_limits<size_type>::max(), n * sizeof(value_type)
is guaranteed
to overflow except when sizeof(value_type) == 1
.
numeric_limits<size_type>::max() / sizeof(value_type)
.
[2015-05, Lenexa]
Marshall: Is this the right solution?
PJP: I think it's gilding the lily.
STL: I think this is right, and it doesn't interact with the incomplete container stuff because it's in a member function.
Marshall: Objections to this?
STL: Spaces around binary operators.
Hwrd: It's completely wrong without spaces.
Marshall: All in favor of Ready?
Lots.
Proposed resolution:
This wording is relative to N4296.
Change 16.4.4.6 [allocator.requirements], Table 28 — "Allocator requirements", as indicated:
Table 28 — Allocator requirements Expression Return type Assertion/note
pre-/post-conditionDefault …
a.max_size()
X::size_type
the largest value that can
meaningfully be passed to
X::allocate()
numeric_limits<size_type>::max()/sizeof(value_type)
…
Change 20.2.9.3 [allocator.traits.members]/p7 as indicated:
static size_type max_size(const Alloc& a) noexcept;Returns:
a.max_size()
if that expression is well-formed; otherwise,numeric_limits<size_type>::max()/sizeof(value_type)
.