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hash
should be std
qualified for unordered containerSection: 23.5 [unord] Status: NAD Submitter: Pete Becker Opened: 2011-02-07 Last modified: 2016-01-28
Priority: Not Prioritized
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View all issues with NAD status.
Discussion:
Tom Plum pointed out to me that there's an apparent inconsistency in the std::
qualification of template names in the unordered containers:
template <class Key, class T, class Hash = hash<Key>, class Pred = std::equal_to<Key>, class Alloc = std::allocator<std::pair<const Key, T> > > class unordered_map;
Is there a reason that hash is not qualified with std::
? TR1 also
does not use std::
here.
[ 2011-02-07 Chris Jefferson adds: ]
I assumed (I might be wrong) it is because hash
is designed to be a
customisation point, like swap
.
[ 2011-02-07 Howard Hinnant adds: ]
I think this is incorrect. We mean std::hash
, though clients
are free to specialize std::hash
on user-defined types. With the
possible exception of begin
/end
(which I'm not sure if
we've settled that), swap
is the only intended customization point (look up a function by ADL) in the std::
lib.
[ 2011-02-24 Chris Jefferson adds: ]
I recommend NAD, due to 16.4.2.2 [contents] p3:
Whenever a name
x
defined in the standard library is mentioned, the namex
is assumed to be fully qualified as::std::x
, unless explicitly described otherwise. For example, if the Effects section for library functionF
is described as calling library functionG
, the function::std::G
is meant.
[2011-02-25 Reflector discussion]
Moved to Tentatively NAD after 5 votes.
Proposed resolution: