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INVOKE
on member data pointer with too many argumentsSection: 22.10.4 [func.require] Status: C++11 Submitter: Howard Hinnant Opened: 2010-10-10 Last modified: 2016-01-28
Priority: Not Prioritized
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Discussion:
20.8.2 [func.require] p1 says:
1 Define
INVOKE(f, t1, t2, ..., tN)
as follows:
(t1.*f)(t2, ..., tN)
whenf
is a pointer to a member function of a classT
andt1
is an object of typeT
or a reference to an object of typeT
or a reference to an object of a type derived fromT
;((*t1).*f)(t2, ..., tN)
whenf
is a pointer to a member function of a classT
andt1
is not one of the types described in the previous item;t1.*f
whenf
is a pointer to member data of a classT
andt1
is an object of typeT
or a reference to an object of typeT
or a reference to an object of a type derived fromT
;(*t1).*f
whenf
is a pointer to member data of a classT
andt1
is not one of the types described in the previous item;f(t1, t2, ..., tN)
in all other cases.
The question is: What happens in the 3rd and
4th bullets when N > 1
?
Does the presence of t2, ..., tN
get ignored, or does it make the
INVOKE
ill formed?
Here is sample code which presents the problem in a concrete example:
#include <functional> #include <cassert> struct S { char data; }; typedef char S::*PMD; int main() { S s; PMD pmd = &S::data; std::reference_wrapper<PMD> r(pmd); r(s, 3.0) = 'a'; // well formed? assert(s.data == 'a'); }
Without the "3.0
" the example is well formed.
[Note: Daniel provided wording to make it explicit that the above example is ill-formed. — end note ]
[ Post-Rapperswil ]
Moved to Tentatively Ready after 5 positive votes on c++std-lib.
[ Adopted at 2010-11 Batavia ]
Proposed resolution:
The wording refers to N3126.
Change 20.8.2 [func.require]/1 as indicated:
1 Define
INVOKE(f, t1, t2, ..., tN)
as follows:
- ...
- ...
t1.*f
whenN == 1
andf
is a pointer to member data of a classT
andt1
is an object of typeT
or a reference to an object of typeT
or a reference to an object of a type derived fromT
;(*t1).*f
whenN == 1
andf
is a pointer to member data of a classT
andt1
is not one of the types described in the previous item;- ...