This is an unofficial snapshot of the ISO/IEC JTC1 SC22 WG21 Core Issues List revision 115e. See http://www.open-std.org/jtc1/sc22/wg21/ for the official list.
2024-11-11
[Voted into WP at October 2005 meeting.]
Consider the following bit of code:
namespace N { struct S { void f(); }; } using namespace N; void S::f() { extern void g(); // ::g or N::g? }
In 6.6 [basic.link] paragraph 7 the Standard says (among other things),
When a block scope declaration of an entity with linkage is not found to refer to some other declaration, then that entity is a member of the innermost enclosing namespace.
The question then is whether N is an “enclosing namespace” for the local declaration of g()?
Proposed resolution (October 2004):
Add the following text as a new paragraph at the end of 9.8.2 [namespace.def]:
The enclosing namespaces of a declaration are those namespaces in which the declaration lexically appears, except for a redeclaration of a namespace member outside its original namespace (e.g., a definition as specified in _N4868_.9.8.2.3 [namespace.memdef]). Such a redeclaration has the same enclosing namespaces as the original declaration. [Example:namespace Q { namespace V { void f(); // enclosing namespaces are the global namespace, Q, and Q::V class C { void m(); }; } void V::f() { // enclosing namespaces are the global namespace, Q, and Q::V extern void h(); // ... so this declares Q::V::h } void V::C::m() { // enclosing namespaces are the global namespace, Q, and Q::V } }—end example]